[newbie] SQL-query with SUM() doesnt work. :(

Hi NG,

I have two tables:

TABLE1 (id1 INTEGER NOT NULL, id2 INTEGER NOT NULL, value INTEGER, PRIMARY KEY (id1, id2))

TABLE2 (id1 INTEGER NOT NULL, text CHAR(4), PRIMARY KEY (id1))

And this is the query, that I'm trying to run on this tables:

select TABLE1.id1, TABLE2.text, sum(TABLE.value)
from table1, table2
where TABLE1.id1=TABLE2.id1
group by TABLE1.id1
order by TABLE1.id1 asc

Well - it doesn't work at all! :(
That is the reason?!

Appreciate everyone's help!!!

S.B.well when doing aggregates you must have everything in the select statement that is not being summed in the group by clause.

Example:

select t1.id1, t2.text, sum(t1.value)
from table1 t1, table2 t2
where t1.id1 = t2.id1
group by t1.id1, t2.text
order by t1.id1 asc|||Hello,

select TABLE1.id1, TABLE2.text, sum(TABLE.value)
from table1, table2
where TABLE1.id1=TABLE2.id1
group by TABLE1.id1
order by TABLE1.id1 asc

DROP the TABLE2.text field cause this is not a group field or
use

select TABLE1.id1, TABLE2.text, sum(TABLE.value)
from table1, table2
where TABLE1.id1=TABLE2.id1
group by TABLE1.id1, TABLE2.text
order by TABLE1.id1 asc

Hope that helps ?

Manfred Peter
Alligator Company Software GmbH
http://www.alligatorsql.com|||Thanks, mkkmg and alligatorsql.com !!! :)

"group by TABLE1.id1, TABLE2.text" works perfectly!

S.B.

Originally posted by alligatorsql.com
Hello,

select TABLE1.id1, TABLE2.text, sum(TABLE.value)
from table1, table2
where TABLE1.id1=TABLE2.id1
group by TABLE1.id1
order by TABLE1.id1 asc

DROP the TABLE2.text field cause this is not a group field or
use

select TABLE1.id1, TABLE2.text, sum(TABLE.value)
from table1, table2
where TABLE1.id1=TABLE2.id1
group by TABLE1.id1, TABLE2.text
order by TABLE1.id1 asc

Hope that helps ?

Manfred Peter
Alligator Company Software GmbH
http://www.alligatorsql.com

[help] Possible to script a diff into SQL Query?

My goal is to add a diff into a query that grabs data from 2 different tables.

The code:
SELECT
MIN(TableName) as TableName,
ID1, COL1, COL2, COL3, COL4, COL5, COL6, COL7, COL8
,COL9, COL10, COL11, COL12, COL13, COL14, COL15, --COL16,
COL17, COL18, COL19, COL20, COL21
FROM
(
SELECT 'Table A' as TableName,
SessionID as ID1,
StartDateCode as COL1,
StartTimeCode as COL2,
EndDateCode as COL3,
EndTimeCode as COL4,
HandledByCode as COL5,
DispositionCode as COL6,
DNISCode as COL7,
CallServiceQueueCode as COL8,
ApplicationCode as COL9,
IVREndPointCode as COL10,
BankCode as COL11,
TotalQueueTimeSS as COL12,
TotalAgentTalkTimeSS as COL13,
TotalAgentHoldTimeSS as COL14,
TotalAgentHandleTimeSS as COL15,
--TotalIVRTimeSS as COL16,
AfterHoursFlag as COL17,
SourceSystemID as COL18,
anubisTransferExtNumber as COL19,
anubisEndPoint as COL20,
AccountNumber as COL21

from [pdx0sql45].Rubicon_Marts.dbo.INB_Call_Fact
where startdatecode between 2738 and 2769

UNION all

SELECT 'Table B' as TableName,
SessionID as ID1,
StartDateCode as COL1,
StartTimeCode as COL2,
EndDateCode as COL3,
EndTimeCode as COL4,
HandledByCode as COL5,
DispositionCode as COL6,
DNISCode as COL7,
CallServiceQueueCode as COL8,
ApplicationCode as COL9,
IVREndPointCode as COL10,
BankCode as COL11,
TotalQueueTimeSS as COL12,
TotalAgentTalkTimeSS as COL13,
TotalAgentHoldTimeSS as COL14,
TotalAgentHandleTimeSS as COL15,
--TotalIVRTimeSS as COL16,
AfterHoursFlag as COL17,
SourceSystemID as COL18,
anubisTransferExtNumber as COL19,
anubisEndPoint as COL20,
AccountNumber as COL21

from pdx0sql04.Rubicon_Marts.dbo.INB_Call_Fact
where startdatecode between 2738 and 2769
) tmp

GROUP BY ID1, COL1, COL2, COL3, COL4, COL5, COL6, COL7, COL8
,COL9, COL10, COL11, COL12, COL13, COL14, COL15, --COL16,
COL17, COL18, COL19, COL20, COL21
HAVING COUNT(*) = 1
ORDER BY 2,1

Is it possible to add a command into the query to output diff/compare scenario?

Thanks in advance for any help.

If you are using SQL Server 2005 you might be able to use the EXCEPT operator instead of the UNION ALL operator. Give a look to the EXCEPT operator in books online.

If the EXCEPT operator looks like it does what you want and it does not perform to your satisfaction, come back and talk to us again. While the EXCEPT operator might be conceptually the most straight forward approach it is not always the most efficient.

Kent

|||Yes, we're using 2005. I'll look into using the EXCEPT op. thanks for the advise, Kent.